Char array passing to function – Computer Sir Ki Class

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Solved Problem #CPP#2656 siteicon   siteicon   siteicon  

Problem Statement - Char array passing to function

Write a function alpha_count() where a character array is passed as reference and the length of array is passed as value. The output of function should be number of alphabets in the input array. You can use function isalpha() if you wish so.

Solution

TC++ #2656

int alpha_count(char str[],int len)
Function definition passed char array of name str[] which is always passed as reference and the integer variable len has been passed as value.
{
int a_count=0; //intialised with 0 will later be incremented inside the loop
for(int i=0;i<len;i++) //Lopp run till the who character array
{
if(isalpha(str[i])) a_count++;  //Check using isalpha() has been done.
}
return a_count;  //The given count is returned to the called place
}

Full Implementation of the function can be seen as below.

#include <iostream>
using namespace std;
int alpha_count(char [],int);
int main()
{
 char str[80];
 int alpha=0;
 cout<<"Input a small sentence: " ;
 cin.getline(str,80);
 int len=strlen(str);
 alpha=alpha_count(str,len);
 cout<<"Number of alphabets in the given input = "
 <<alpha<<endl; 
 return 0;
}

int alpha_count(char str[],int len)
{
 int a_count=0;
 for(int i=0;i<len;i++)
 {
 if(isalpha(str[i])) a_count++;
 }
 return a_count;
}

 

Notes

  • Array passing can also be done using pointer like this –
    int alpha_count(char* str,int len)


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sunmitra| Created: 15-Jan-2018 | Updated: 15-Jan-2018|






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