22.345

22.345

34.204345703125

2234.5

0.22345

Code Understanding

float a=22.345f;
The value 22.345f here is a float type literal constant. f is suffixed to differentiate it from double. If you do not suffix it is treated as double value and you can not store it in a float type. Float needs 32 bits of storage

double b=22.345;
Here the value 22.345 is double type literal constant .  Double needs 64 bits of storage.

double c=0x22.345P0;
This is double value shown in hexadecimal notation. This is equivalent to 22 in hex form and then .345 in hex form with Power of 2 as 0 as its multiple.

double d=22.345E2;
This is exponent form which is equivalent to 22.345 x 10^2 which means 2234.5

double e=22.345E-2;
This is negative exponent form which is equilent to 22.345×10^-2 which means 0.22345

System.out.println(a); System.out.println(b); System.out.println(c); System.out.println(d); System.out.println(e);
Here we print all the decimal equivalents of above.

Notes

• Exponent notation can allow a value of storage in double data type which is bigger than its no. of bits equivalent.

Suggested Filename(s): DecimalLiterals.java