Output writing – Possible Random Numbers – Computer Sir Ki Class


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Exam Questions-CBSE12A-2018-01F #CPP#5224    siteicon   siteicon  

Problem Statement - Output writing – Possible Random Numbers

Look at the following C++ code and find the possible output(s) from the options (i) to (iv) following it. Also, write the highest and lowest values that can be assigned in the array A.
Note :
● Assume all the required header files are already being included in the code.
● The function random(n) generates an integer between 0 and n-1.


void main()
  int A[4], C;
  for(C=0; C<4; C++)
  for(C=3; C>=0; C--)


(i)   13@10@11@10@             (ii)   15$14$12$10$
(iii) 12@11@13@10@             (iv)  12@11@10@10@


TC++ #5224

Possible outputs could be
(i)  13@10@11@10@
(iv) 12@11@10@10@

A (Min)  = 10
A (Max) = 13



This will allow random number generation process.

int A[4], C;
Integer array A with four members and and a counter variable C has been declared.

for(C=0; C<4; C++) //This will handle the array in forward order
Since value of C would be 0 to 3 in increasing order the possible random values on R.H.S could be 10 to 13. When it is 0 number could be 1o, when it is 3 the number could be 10/11/12/13 on R.H.S. . So the array would be filled by numbers from 10 to 13. The possible value chart could be

index 0  |  index 1  | index 2      | index 3
10,            10/11,     10/11/12,    10/11/12/13

for(C=3; C>=0; C–)   cout<<A[C]<<“@”;
This will print the possible values in the array but from the last member (at index 3)to the first member at index 0. Based on possible value chart only option (i) and option (iv) are possible. Remember that you are reading array from last to the beginning.

  • Remember that random number generation is 1 less than the maximum value passed to random function. So random(1) will be 0, random(2) would be 0 or 1, random(3) would 0, 1 or 2, random(4) would 0, 1, 2 or 3

Common Errors

  • Student may forget that while printing the array is being read in the reverse order.


CSKC| Created: 3-Dec-2018 | Updated: 4-Dec-2018|CBSE12A-2018

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