Simple user input in integer form

Code Learning #CPP#1712

Learning the ways to take simple user input in integer form.

Learning Objectives

Collecting simple user input in an integer form.
use of cin and io extraction operator.

Program Approach

Create an space where the user input would be stored.
Prompt the user for an input using the cout.
Collect the user input using cin and >> (io extraction operator)
Display the input given by the user.

Source Code

Run Output

Enter an integer number: 23

You have entered 23



or



Enter an integer number: 23.45

You have entered 23

Code Understanding

int n;
Here we declare a variable of our choice. In this case we have named it n. For this we decide to use the integer data type.

cout<<“Enter an integer number: “;
This line is used to prompt the user what has to be input.

cin>>n;
This is the line which collects the user input using the cin object in c++.. This object is followed by >> operator which is also called the “io extraction operator”. Some literature also name it as the “get from console” operator.

cout<<“You have entered “<<n<<endl;
This line is used to display the output as entered by the user. n is the variable which will be filled by the user when cin collects the required data.

Notes

In this code if user input is not an integer,say it is a fraction value like 23.45, then cin will still collect it. But! since the storage variable n is of integer type, thus the stored value will only be the integer portion of the input. So the output will only be 23.

Suggested Filename(s): simpleinput.cpp, intinput.cpp

CSKC| Created: 14-Dec-2017 | Updated: 31-Aug-2018|

Post Views: 512

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Example(s):Palindrome, prime, armstrong, "linear search", reverse etc.


Example(s):1575, 1632, 1539 (Only one at a time)

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