Simple user input in integer form – Computer Sir Ki Class


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Simple user input in integer form

Learning the ways to take simple user input in integer form.

Learning Objectives

  • Collecting simple user input in an integer form.
  • use of cin and io extraction operator.

Program Approach

  • Create an space where the user input would be stored.
  • Prompt the user for an input using the cout.
  • Collect the user input using cin and >> (io extraction operator)
  • Display the input given by the user.

Source Code

TC++ #1712


Source Code

Run Output

Enter an integer number: 23
You have entered 23


Enter an integer number: 23.45
You have entered 23

Code Understanding

int n;
Here we declare a variable of our choice. In this case we have named it n. For this we decide to use the integer data type.

cout<<“Enter an integer number: “;
This line is used to prompt the user what has to be input.

This is the line which collects the user input using the cin object in c++.. This object is followed by >> operator which is also called the “io extraction operator”. Some literature also name it as the “get from console” operator.

cout<<“You have entered “<<n<<endl;
This line is used to display the output as entered by the user. n is the variable which will be filled by the user when cin collects the required data.


In this code if user input is not an integer,say it is a fraction value like 23.45, then cin will still collect it. But! since the storage variable n is of integer type, thus the stored value will only be the integer portion of the input. So the output will only be 23.

Suggested Filename(s): simpleinput.cpp, intinput.cpp


CSKC| Created: 14-Dec-2017 | Updated: 31-Aug-2018|

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