Question:
Derive a Canonical POS expression for a Boolean function G, represented by the following truth table:
X | Y | Z | G(X,Y,Z) |
---|---|---|---|
0 | 0 | 0 | 0 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 1 |
0 | 1 | 1 | 0 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 1 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 |
CSKC| Created: 3-Jan-2019 | Updated: 5-Jan-2019|CBSE12A-2017