Question:
Derive a Canonical SOP expression for a Boolean function F, represented by the following truth table:
A | B | C | F(A,B,C) |
---|---|---|---|
0 | 0 | 0 | 1 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 0 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 0 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 |
CSKC| Created: 5-Jan-2019 | Updated: 5-Jan-2019|CBSE12D-2015